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14. Program to find the square and find whether it is a perfect square

# Program to find and check the perfect square

b=0
def square(digit):
    while True:
        for i in range(0,int(digit/2)):
            b=i*i
            if(b==digit):
                return(i)
        if(b!=digit):
           return(-555)y
number=int(input('enter the number to be find perfect square root '))
a=square(number)
if(number==a*a):
    print(number,' is a perfect square')
    print('the square root of',number,'is',a)
else:
    print('Since!',number,'is not a perfect square of any number ')
    print('sorry! ',number,'does not have  perfect square root')


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