14. Program to find the square and find whether it is a perfect square

# Program to find and check the perfect square

b=0

def square(digit):

    while True:

        for i in range(0,int(digit/2)):

            b=i*i

            if(b==digit):

                return(i)

        if(b!=digit):

           return(-555)y

number=int(input('enter the number to be find perfect square root '))

a=square(number)

if(number==a*a):

    print(number,' is a perfect square')

    print('the square root of',number,'is',a)

else:

    print('Since!',number,'is not a perfect square of any number ')

    print('sorry! ',number,'does not have  perfect square root')