14. Program to find the square and find whether it is a perfect square

# Program to find and check the perfect square

b=0

def square(digit):

while True:

for i in range(0,int(digit/2)):

b=i*i

if(b==digit):

return(i)

if(b!=digit):

return(-555)y

number=int(input('enter the number to be find perfect square root '))

a=square(number)

if(number==a*a):

print(number,' is a perfect square')

print('the square root of',number,'is',a)

else:

print('Since!',number,'is not a perfect square of any number ')

print('sorry! ',number,'does not have perfect square root')

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